On Tue, Dec 02 2003 at 06:04:42pm +0100, Gunther.Mayer-at-t-online.de (Gunther Mayer) |v4l| wrote: > Hi, Hi again > which card is this ? It is a Pinnacle PCTV Pro (red card) > Can you send more "dmesg" output ? after modprobe tuner debug=1 and modprobe bttv i2c-core.o: driver i2c TV tuner driver registered. bttv: driver version 0.7.107 loaded bttv: using 4 buffers with 2080k (8320k total) for capture bttv: Host bridge is VIA Technologies, Inc. VT8363/8365 [KT133/KM133] bttv: Host bridge is VIA Technologies, Inc. VT82C686 [Apollo Super ACPI] bttv: Bt8xx card found (0). PCI: Found IRQ 10 for device 00:08.0 PCI: Sharing IRQ 10 with 00:08.1 PCI: Sharing IRQ 10 with 00:0c.0 bttv0: Bt878 (rev 17) at 00:08.0, irq: 10, latency: 32, mmio: 0xe3008000 bttv0: detected: Pinnacle PCTV [card=39], PCI subsystem ID is 11bd:0012 bttv0: using: BT878(Pinnacle PCTV Studio/Ra) [card=39,autodetected] msp34xx: init: chip=MSP3410G-B11 +nicam +simple +radio msp3410: daemon started i2c-core.o: client [MSP3410G-B11] registered to adapter [bt848 #0](pos. 0). tvaudio: found pic16c54 (PV951) @ 0x96 i2c-core.o: client [pic16c54 (PV951)] registered to adapter [bt848 #0](pos. 1). tuner: chip found @ 0xc0 i2c-core.o: client [(tuner unset)] registered to adapter [bt848 #0](pos. 2). i2c-core.o: adapter bt848 #0 registered as adapter 0. bttv0: i2c: checking for MSP34xx @ 0x80... found bttv0: pinnacle/mt: id=2 info="PAL+SECAM / stereo" radio=yes bttv0: using tuner=33 tuner: pinnacle pal tuner: type set to 33 (MT2032/MT2050) tuner: MT2050 detected. tuner: MT20xx hexdump: 42 8f 1c cb 66 63 10 88 29 09 85 99 e3 96 f0 14 24 3c bf 42 8f mt2050 sro is 96 bttv0: i2c: checking for MSP34xx @ 0x80... found bttv0: i2c: checking for TDA9875 @ 0xb0... not found bttv0: i2c: checking for TDA7432 @ 0x8a... not found bttv0: PLL: 28636363 => 35468950 .. ok bttv0: registered device video0 bttv0: registered device vbi0 bttv0: registered device radio0 and after trying to tune in to a channel: tuner: tv freq set to 189.25 mt2050_set_if_freq freq=189250000 lo1 lo2 = 351 294 num1 num2 div1a div1b div2a div2b= 3 b66 1c 3 23 6 bufs is: 1 8f 1c cb 66 63 > Regards, Gunther Kind Regards, Daniel
